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7x^2-49x-30=0
a = 7; b = -49; c = -30;
Δ = b2-4ac
Δ = -492-4·7·(-30)
Δ = 3241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-49)-\sqrt{3241}}{2*7}=\frac{49-\sqrt{3241}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-49)+\sqrt{3241}}{2*7}=\frac{49+\sqrt{3241}}{14} $
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